For "Mathaletes"

If anyone is interested in running a few "math" miles today, here is a nice word problem that I am going to attempt to explain in full!   
  h= -16t^2 + 80t + 64   where t= time in seconds & h= height 
  This formula is a "quadratic equation" for finding the curve of an object as it falls, when it hits the ground etc.
        This ^ means that anything after the symbol, means that the number or variable is a power. 
             What time will the ball obtain maximum height?  
                                   SPOILER
 First, not knowing the math levels of my audience ( but I am assuming some or most of you have taken algebra 1)  I must explain a few things. For this question we will be using part of the "Quadratic Formula". -b/2a. By now you are probably extremely lost and about to skip. B, is always the number in front of t that isn't squared, so in this case 80 is b. That would make a -80 for b. Now we have -80/2a. A is always the number that is squared so in this case it would be 2(-16). Now we have -80/2(-16).
   Simplify the fraction -80/2(-16) into + 5/2. That simply leaves us with 2 and 1/2 sec when you divide five by two. 


               So in other words, the ball with obtain maximum height in two and a half seconds. 
       A= -16
       B= 80 
           Where we get the numbers    h= a^2 + b(t) + 64.
               -80/2(-16) turns into 5/2 then once divided turns into 2 and 1/2 seconds. t = time in seconds. 
           Alrighty, well that's a good 20 math miles for everyone.. considering that the equation was one of the grand finales of Algebra 1 that you needed to take the whole class to do. 
                 see ya!

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